In: Statistics and Probability
From a group of 4 women and 6 men, a committee of 4 members will be elected. a) How many committees can you choose? b) How many committees can be elected if there should be 3 men? c) How many committees can be elected if there should be at least one woman? d) If you want to choose a directive, that is, a president, vice president, treasurer and secretary, in how many ways can you choose? e) If the whole group wants to sit down, all in a row, in how many different ways can they be done? f) If the whole group wants to sit down, all in a row, in how many different ways can they be done, if to take if Pepito and Pepita want to be together? g) If the whole group wants to sit, all in a row. How many different ways can be done if women are together and men are together?
(b)
3 Men can be selected from 6 Men in:
ways
1 Woman can be selected from 4 Women in
ways
So,
Number of committees = 20 X 4 =80
So,
Answer is:
80
(c)
Total number of committees is given by:
4 Members can be selected from 10 Members in:
ways
Number of committees without any Woman is given by:
4 Men can be selected from 6 Men in:
So,
Number of Committees with at least 1 Woman = 210 - 15 = 195
So,
Answer is:
195
(d)
President can be selected in 10 ways
Vice president can be selected in 9 ways
Treasurer can be selected in 8 ways
Secretary can be selected in 7 ways
So,
Total number of ways = 10 X 9 X 8 X 7 = 5040
So,
Answer is:
5040
(e)
Number of ways = 10! = 3628800
So,
Answer is:
3,628,800
(f)
Consider Pepito and Popita as one person.
Number of ways of arranging 9 persons = 9! = 362,880
Pepito and Pepita can be arranged in 2ways.
So,
Number of ways = 362,880 X 2 = 725,760
So,
Answer is:
725,760
(g)
Consider all Men as1 person. All Women as1 person.
There 2 persons can be arranged in 2! = 2 ways
6 Men can be arranged in 6! = 720 ways
4 Women can be arranged in 4! = 24 ways
So
Total number of ways = 2 X 720 X 24 = 34,560 ways
So,
Answer is:
34,560