In: Math
A manager wishes to determine whether the mean times
required to complete a certain task differ for two levels of
employee training. He randomly selected seven employees with each
of the two levels of training (Beginner and Advanced). Further, he
wants to know if the time (in minutes) is different for males and
females. The data is summarized in the table.
Employee
Male
Female
Male
Female
1
20.3
14.3
15.2
19.3
2
19.7
19.5
14.2
18.4
3
27.6
16.5
8.9
18.1
4
25.8
13.8
9.7
15.9
5
26.2
12.4
10.5
17.8
6
20.4
11.8
15.1
17.0
7
24.3
14.2
12.0
16.8
Total
164.3
102.5
85.6
123.3
Mean
23.47
14.64
12.22
17.61
GT
164.3+102.5+85.6+123.3=475.7
A manager wishes to determine whether the mean times required to complete a certain task differ for two levels of employee training. He randomly selected seven employees with each of the two levels of training (Beginner and Advanced). Further, he wants to know if the time (in minutes) is different for males and females.
To test the effect of employee training, calculated F= 18.58, P=0.0002 which is < 0.05 level of significance. Training is significant.
To test the effect of gender calculated F= 3.22, P=0.0854 which is > 0.05 level of significance. Gender is not significant.
Excel Addon Megastat used.
Two factor ANOVA |
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Factor 2 |
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Means: |
|||||
Male |
Female |
||||
Beginner |
23.47 |
14.64 |
19.06 |
||
Factor 1 |
Advanced |
12.23 |
17.61 |
14.92 |
|
17.85 |
16.13 |
16.99 |
|||
7.0000 |
replications per cell |
||||
ANOVA table |
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Source |
SS |
df |
MS |
F |
p-value |
Factor 1(Training) |
119.729 |
1.0000 |
119.7289 |
18.58 |
.0002 |
Factor 2(Gender) |
20.743 |
1.0000 |
20.7432 |
3.22 |
.0854 |
Interaction |
353.580 |
1.0000 |
353.5804 |
54.86 |
1.20E-07 |
Error |
154.674 |
24.0000 |
6.4448 |
||
Total |
648.727 |
27.0000 |