Question

In Python: 1 line short expressions

a. Assume that x is a variable that has been given a string value. Write an expression whose value is True if and only if x is an octal (Base 8) digits (0-7)

b. Assume that x is a variable that has been given a string value. Write an expression whose value is True if and only if x is an letter.

c. Assume that x is a variable that has been given a string value. Write an expression whose value is True if and only if x is a hexadecimal (Base 16) digit(0-9 plus A-F or a-f).

Answer 1

Q43)

a ) In octal we have digit range from 0 - 7 .

So when we have x and if we give it string then it will be in form of '0' , '1' , '2' ,... till '7'

Hence expression will that value of x must be greater than equal to 0 and less than equal to 7 .

Expression that will be : (x>='0' and x<='7')

Here we use and operator when both will be true

b) If x is a letter then it ranges from 'A' to 'Z' or 'a' to 'z'

Similarly check x for both either it is in Upper case or lower case and expression will be true when one is true

Expression that will be : (x>='A' && x<='Z') or (x>='a' && x<='z')

Here we use or operator so it will be true if any one is true

c) If x is hexadecimal then it ranges from 0 to 9 then we have A to F or we have 'a' to 'f' .

SO to write the expression we have to combine three checks i.e. First 0 to 9 Second a to f third A to F , If any one is true then expression is true

Expression that will be : (( x>='0' && x<='9') or ( x>='a' && x<='f' ) or ( x>='A' && x<='F'))

This is how we can write all three expression in one line in Python for each part

Thank You

If u like the answer then do Upvote it and have any doubt ask in comments