Question

A physician wants to develop criteria for determining whether a​ patient's pulse rate is​ atypical, and she wants to determine whether there are significant differences between males and females. Use the sample pulse rates below.

Male 96 76 56 72 64 68 68 88 76 72

Female 68 104 104 96 72 60 60 96 84 124

Construct a 95​% confidence interval estimate of the mean pulse rate for FEMALES.

< μ <

Answer 1

SOLUTION:

From given data,

the sample pulse rates below.

Male 96 76 56 72 64 68 68 88 76 72

Female 68 104 104 96 72 60 60 96 84 124

Construct a 95​% confidence interval estimate of the mean pulse rate for FEMALES.

Female(x_i )= 68 104 104 96 72 60 60 96 84 124

Where n =10

= ( 68 +104+ 104 +96+ 72+ 60+ 60+ 96+ 84+ 124) 10

= 868 10

Mean = = 86.8

Sample standard deviation:

now, calculating

(68-86.8)²+(104-86.8)²+(104-86.8)²+(96-86.8)²+(72-86.8)²+(60-86.8)²

+(60-86.8)²+(96-86.8)²+(84 -86.8)²+(124-86.8)²

353.44+295.84+295.84+84.64+219.04+718.24+718.24+84.64+7.84+1383.84

4161.6

Now calculating s

level of significance=

= 1-0.95

= 0.05

Degree of freedom(df):

n-1 = 10-1

= 9

critical value t_/2,df :

t_/2,df = t_0.05/2,9

= t_0.025,9

t_/2,df = 2.262

A 95​% confidence interval estimate of the mean pulse rate for FEMALES is

86.8(2.262)(2.150)

86.64.864089

[(86.6-4.864089) , (86.6+ 4.864089)]

[81.74 , 91.46]