In: Math
The data for a random sample of 10 paired observations are shown in the following table.
Pair | Population1 | Population 2 |
1 | 19 | 24 |
2 | 25 | 27 |
3 | 31 | 36 |
4 | 52 | 53 |
5 | 49 | 55 |
6 | 34 | 34 |
7 | 59 | 66 |
8 | 47 | 51 |
9 | 17 | 20 |
10 | 51 | 55 |
If you wish to test whether these data are sufficient to indicate that the mean for population 2 is larger than that for population 1, what are the appropriate null and alternative hypotheses? Define any symbols you use.
Conduct the test from part a, using α=.05. What is your decision?
Find a 95% confidence interval for μd. Interpret this interval.
What assumptions are necessary to ensure the validity of the preceding analysis?
let us consider =
population 1 mean
=
population 2 mean
to test whether these data are sufficient to indicate that the mean for population 2 is larger than that for population 1
let =
H0 :
Ha:
using minitab > paired sample t test > we have
Paired T-Test and CI: Population1, Population 2
Paired T for Population1 - Population 2
N Mean StDev SE Mean
Population1 10 38.40 15.06 4.76
Population 2 10 42.10 15.81 5.00
Difference 10 -3.700 2.214 0.700
95% upper bound for mean difference: -2.417
T-Test of mean difference = 0 (vs < 0): T-Value = -5.29 P-Value
= 0.000
since p value is less than 0.05 so we reject h0 and conclude that the mean for population 2 is larger than that for population
95% CI for mean difference: (-5.284, -2.116)
since the confidence interval of difference of mean of two populations contains only negative values so we can be 95 % confident that population mean difference lies in between this interval .
the assumption required are the sample taken should be random and on same observations. and the sample should be taken from normally distributed population.