Carbon-14 decays as follows: 14 0 14 &

Carbon-14 decays as follows:

_{14
0
14}

C ----> e + N

^{6
-1
7}

isotopic masses are 14.00307 for nitrogen-14 and 14.00324 for carbon-14. What energy change (kJ/moles) occurs in the beta decay of C-14? NOTE: Do I use these two masses to get the mass defect or do I use the mass of protons and nuetrons to find the mass defect of each one and then subtract the two?

Expert Solution

mass defect = mass of product - mass of reactant

= (14.00307 + 0.000548579 ) - 14.00324

= 0.0003785799 amu

1 amu =1.66053892 × 10^-27 kilograms

mass defect in Kg = = 0.0003785799 x 1.66053892 × 10^-27 = 6.286 x 10^-31 kilograms

binding energy = mass defect x C^2

= 6.286 x 10^-31 x (3 x10^8)^2

= 5.6576 x 10^-14 J

= 5.6576 x 10^-17 kJ ( divide by avagadro number = 6.023 x10^23 )

= 3.40 x 10^10 kJ /mol

queen_honey_blossom answered 1 year ago

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