In: Physics
Problem 22.29
What magnitude charge creates a 1.70 N/C electric field at a point 4.60 m away? Express your answer with the appropriate units. Thanks ;)
Given data:
Electric Field (E) = 1.70 N/C
Separation Distance (d) = 4.60 m
Formula for Electric field strength (E) = Q/4d2
The magnitude of charge (Q) = E 4d2
(Q) = 1.7 X 4 X 3.14 X 8.85 X 10-12 X 4.6 X 4.6
Answer : Q = 3998.304 X 10-12 columbs