Question

A 44.0 kg body is moving in the direction of the positive x-axis with a speed of 373 m/s when owing to an internal explosion, it breaks into three pieces. One part, whose mass is 6.5kg, moves away from the point of explosion with a speed of 438 m/s along the positive y-axis. A second fragment, whose mass is 5.0 kg, moves away from the point of explosion with a speed of 378 m/s along the negative x-axis.

What is the speed of the third fragment? Ignore effects due to gravity.  

How much energy was released in the explosion?

Answer 1

Before explosion

Given Mass of Main body , M = 44 kg

initial velocity of Main body , U = 373m/s in x direction

After explosion

Mass of body 1 ,m₁ = 6.5kg

Final velocity of body1 ,v₁ = 438 m/s in y direction(v_1y)

Mass of body 2 ,m₂ = 5 kg

Final velocity of body2 ,v₂ = 378 m/s in -ve x direction (v_2x)

Mass of body 3 ,m₃ = 32.5kg

Final velocity of body3 ,v₃ = ?

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Momentum is Conserved

Consider Conservation of momentun in x direction

PE_{x initial} =PE_{x final}

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Consider Conservation of momentun in y direction

PE_{y initial} =PE_{y final}

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ANSWER: Speed of the third fragment

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Energy released in the explosion =change in Kinetic energy

KE_initial = =

KE_final =

ANSWER:

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