Question

In: Computer Science

Consider the following segment table: Segment Base Length 0 219 600 1 2300 14 2 90...

Consider the following segment table:

Segment Base Length

0 219 600

1 2300 14

2 90 100

3 1327 580

4 1952 96

What are the physical addresses for the following logical addresses?

0,430
1,10
2,500
3,400
4,112

Expert Solution

Given segment table:
Segment-Base-Length
0-219-600
1-2300-14
2-90-100
3-1327-580
4-1952-96
What are the physical addresses for the following logical addresses?

Here, The Physical address is calculated as Base+FrameNumber

Question 1) 0,430
Ans: 649
For this, the Base is 219 and the Frame number is 430 ==> 219+430=649

Question 2) 1,10
Ans: 2310
For this, the Base is 2300 and the Frame number is 10 ==> 2300+10=2310

Question 3) 2,500
Ans: Illegal reference
It is because the base value is 90 and length is 100 Adding it will give 190
Now add Base+FrameNumber ==> 90+500=590 which is much greater than 190. so it holds an illegal reference.

Question 4) 3,400
Ans: 1727
For this the Base is 1327 and the Frame number is 400 ==> 1327+400-1727

Question 5) 4,112
Ans: Illegal reference
It is because the base value is 1952 and length is 96 Adding it will give 2048
Now add Base+FrameNumber ==> 2064 which is much greater than 2048.so it holds an illegal reference.

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venereology answered 2 years ago

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