In: Statistics and Probability
How do I find the lower limit of a confidence interval using a z-table. Having trouble understanding where the 1.645 number came from in this solution
Sample proportion {p} = 367 / 561 = 0.654 Lower limit for 95% confidence interval is {p} - Z\alpha * sqrt( {p} ( 1 - {p} ) / n) = 0.654 - 1.645 * sqrt( 0.654 * 0.346 / 561) = 0.617