In: Statistics and Probability
Vehicle Name | Weight |
Cadillac CTS VVT 4dr | 3694 |
Cadillac Deville 4dr | 3984 |
Cadillac Deville DTS 4dr | 4044 |
Cadillac Seville SLS 4dr | 3992 |
Lincoln LS V6 Luxury 4dr | 3681 |
Lincoln LS V6 Premium 4dr | 3681 |
Lincoln LS V8 Sport 4dr | 3768 |
Lincoln LS V8 Ultimate 4dr | 3768 |
Lincoln Town Car Signature 4dr | 4369 |
Lincoln Town Car Ultimate 4dr | 4369 |
Lincoln Town Car Ultimate L 4dr | 4474 |
In what follows use any of the following tests/procedures: Regression, multiple regressions, confidence intervals, one-sided t-test or two-sided t-test. All the procedures should be done with 5% P-value or 95% confidence interval
Upload CARS data. SETUP: It is believed that Lincolns are heavier than Cadillac. Given the data your job is to confirm or disprove this belief. (CAREFULL: sort the data in order to extract the needed information).
9. What test/procedure did you perform?
10. What is the P-value/margin of error?
11. Statistical Interpretation
12. Conclusion
Task 2
(9) One-sided t test
(10)
Data:
n1 = 7
n2 = 4
x1-bar = 4015.71
x2-bar = 3928.5
s1 = 366.62
s2 = 158.58
Hypotheses:
Ho: μ1 ≤ μ2
Ha: μ1 > μ2
Decision Rule:
α = 0.05
Degrees of freedom = 7 + 4 - 2 = 9
Critical t- score = 1.83311292
Reject Ho if t > 1.83311292
Test Statistic:
Pooled SD, s = √[{(n1 - 1) s1^2 + (n2 - 1) s2^2} / (n1 + n2 - 2)] = √(((7 - 1) * 366.62^2 + (4 - 1) * 158.58^2)/(7 + 4 - 2)) = 313.0325144
SE = s * √{(1 /n1) + (1 /n2)} = 313.032514392142 * √((1/7) + (1/4)) = 196.2035118
t = (x1-bar -x2-bar)/SE = (4015.71 - 3928.5)/196.203511849061 = 0.444487457
p- value = 0.3335932
Decision (in terms of the hypotheses):
Since 0.44448746 < 1.833112923 we fail to reject Ho
Conclusion (in terms of the problem):
There is no sufficient evidence that Lincolns are heavier than Cadillac
p- value answer: None of these
(11) None of these
(12) Yes, I am confident that the above assertion is correct