Three people, X, Y, Z, in order roll an ordinary die. The first
one to roll...
Three people, X, Y, Z, in order roll an ordinary die. The first
one to roll an even number wins. The game continues until someone
rolls an even number. Determine the probability that either Y or Z
will win.
1) If x, y, z are consecutive integers in order then 9 | (x+y+z)
⟺ 3 | y. (Do proof)
2) Let x, y be consecutive even integers then (x+y) is not
divisible by 4. (Show proof and state why it was used)
Let z=e^(x) tan y.
a. Compute the first-order partial derivatives of z.
b. Compute the second-order partial derivatives of z.
c.∗ Convert z = f(x,y) into polar coordinates and then compute
the first- order partial derivatives fr and fθ by directly
differentiating the com- posite function, and then using the Chain
Rule.
The newest invention is a three-sided die. On any roll of this
die, the result is 1 with probability 1/2, 2 with probability 1/4,
and 3 with probability 1/4.
Consider a sequence of six independent rolls of this die.
A. Find the probability that exactly two of the rolls result in
a 3.
B. Given that exactly two of the six rolls resulted in a 1, find
the probability that the first roll resulted in a 1.
C. We are...
The full three-dimensional Schrödinger equation is
−ℏ22m(∂2∂x2ψ(x,y,z)+∂2∂y2ψ(x,y,z)+∂2∂z2ψ(x,y,z))+U(x,y,z)ψ(x,y,z)=Eψ(x,y,z).
By using the substitutions from the introduction, this
becomes
−ℏ22m(∂2∂x2ψxψyψz+∂2∂y2ψxψyψz+∂2∂z2ψxψyψz)+(Ux+Uy+Uz)ψxψyψz=Eψxψyψz
What is ∂2∂x2ψxψyψz? To make entering the expression easier, use
D2x in place of d2ψxdx2, D2y in place of d2ψydy2, and D2z in place
of d2ψzdz2.
Answer in terms of ψx,ψy,ψz,D2x,D2y,andD2z
We roll two fair dice (a black die and a white die). Let
x = the number on the black die − the number on the white
die,record x as the outcome of this random experiment.
(a) What is the probability space?
The curried version of let f (x,y,z) = (x,(y,z)) is
let f (x,(y,z)) = (x,(y,z))
Just f (because f is already curried)
let f x y z = (x,(y,z))
let f x y z = x (y z)