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Question: Given the following information set up the problem in a transportation table and solve for the mi...
Given the following information set up the problem in a transportation table and solve for the minimum-cost plan:
PERIOD | ||||
1 | 2 | 3 | ||
Demand | 550 | 700 | 750 | |
Capacity | ||||
Regular | 500 | 500 | 440 | |
Overtime | 50 | 50 | 50 | |
Subcontract | 120 | 120 | 100 | |
Beginning inventory | 100 | |||
Costs | ||||
Regular time | $ | 60 per unit | ||
Overtime | $ | 80 per unit | ||
Subcontract | $ | 90 per unit | ||
Inventory carrying cost | $ | 1 per unit per month | ||
Back-order cost | $ | 3 per unit per month | ||
Suppose that an inventory carrying cost is increased $2 per unit
per period. What will the additional cost of the optimal
plan be?
I have asked this question a couple times and it has been incorrect. The answer is not $440.... good luck!
Hi, first of all, I am using excel solver to optimize the solution. The assumption is that the production cannot exceed the mentioned capacity for a period.
Step 1
Setup the solution, define the regular, overtime and subcontract units as decision variables. Form the equations, constrains, and the “if” conditions. (I am assuming you know how to do this. In case if you don’t, let me know in the comment section and I will provide you with the formulas). Here, the total unis is the summation of total product across the 3 periods and the beginning inventory.
Step 2
Us the total cost as minimizing objective function and use the constraints as shown in the screenshot.
Step 3
Obtain the optimal solution by running solver. Shown in the screenshot. The total cost at this point is $126960
Step 4
Change the value of Carrying (B19) to 2 and rerun the solver. Record the total cost. The total cost at this point is $127050. Hence the difference of making carrying cost from $1 to $2 is $90.
Hope this helps. Cheers!