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In: Statistics and Probability

A radio station runs a promotion at an auto show with a money box with 14...

A radio station runs a promotion at an auto show with a money box with 14 ​$25 ​tickets, 11 ​$5 ​tickets, and 15 ​$1 tickets. The box contains an additional 20 ​"dummy" tickets with no value. Three tickets are randomly drawn. Find the probability that all three tickets have no value. The probability that all three tickets drawn have no money value is..... ​(Round to four decimal places as​ needed.)

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Expert Solution

Solution:

We are given that a radio station runs a promotion at an auto show with a money box with:

14 ​$25 ​tickets,

11 ​$5 ​tickets,

15 ​$1 tickets,

and

20 ​"dummy" tickets with no value

Thus total Tickets are = 14 + 11 + 15 + 20 = 60

Three tickets randomly selected and we have to find the probability that all three tickets have no value.

Thus all three tickets are selected from those 20 tickets which has no value.

Thus

P( all three tickets have no value )  

We use combination formula:

Thus

and

P( all three tickets have no value )  

Thus

P( all three tickets have no value )   = 0.0333

orchestra answered 2 years ago
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