A radio station runs a promotion at an auto show with a money box with 14...

A radio station runs a promotion at an auto show with a money box with 14 $50 tickets, 10 $25 tickets, and 15 $5 tickets. The box contains an additional 20 "dummy" tickets with no value. Three tickets are randomly drawn. Find the probability that all three tickets have no value. The probability that all three tickets drawn have no money value is nothing. (Round to four decimal places as needed.)

Solutions

Expert Solution

Total tickets = 14 + 10 + 15 + 20 = 59

P(all 3 tickets have no value) = 20C3 / 59C3 = 1140 / 32509 = 0.0351 (ans)

milcah answered 2 days ago

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