Question

In: Civil Engineering

A 16-ft long pin-pin column has to support a dead load of 100 kips and a...

A 16-ft long pin-pin column has to support a dead load of 100 kips and a live load of 280 kips. Using column selection tables from the Steel Manual select columns for the given shapes. All selections should be structurally safe and least weight.

50-ksi W-section (W10, 12, 14 only)

35-ksi pipe (standard, x-strong, xx-strong)

46-ksi rectangular HSS

46-ksi square HSS

42-ksi round HSS

Solutions

Expert Solution


Related Solutions

A 16-ft long pin-pin column has to support a dead load of 100 kips and a...
A 16-ft long pin-pin column has to support a dead load of 100 kips and a live load of 280 kips. Using column selection tables from the Steel Manual select columns for the given shapes. All selections should be structurally safe and least weight. 50-ksi W-section (W10, 12, 14 only) 35-ksi pipe (standard, x-strong, xx-strong) 46-ksi rectangular HSS 46-ksi square HSS 42-ksi round HSS
steel structure Q1. The column carries 60 kips dead load and 40 kips live load, its...
steel structure Q1. The column carries 60 kips dead load and 40 kips live load, its length is 20 ft, and the steel is A992. Assume the member as pinned at the top and bottom. (a) Compute Pa; (b) Determine the effective length (KL); (c) Use ASD method to select the lightest W section; (d) Check the local buckling slenderness limits of the selected section.
A 40 ft simple span beam is loaded with a uniform dead load of 2.4 kips/ft...
A 40 ft simple span beam is loaded with a uniform dead load of 2.4 kips/ft plus the beam self-weight and a uniform live load of 3.3 kips/ft. The lateral supports are located at the supports and at the midpoint of the span. Determine the leastweight W-shape to carry the load. Use A992 steel and Cb= 1.0. Design by (a) LRFD and (b) ASD. [6.16-36]
Determine the maximum live load that a column W14x193 could support if the dead load is...
Determine the maximum live load that a column W14x193 could support if the dead load is ten times the live load. Use A-36 with K=1 and L=22 ft.
Select a 12 ft cantilever beam with p = 0.012, to support a dead load of...
Select a 12 ft cantilever beam with p = 0.012, to support a dead load of 2k/f (including self weight) and Live load of 3 k/ft. fy= 60000 psi, fc'= 3500 psi (hint your answer should be Width = XXXX, Effective depth= XXXXX, Area of reinforcement = XXXXX)
W shape column must support a axial load (DL=500 kips y LL= 300 kips). The element...
W shape column must support a axial load (DL=500 kips y LL= 300 kips). The element is 30 ft length and braced in the y direction at 14 ft from the column base. The end support conditions are (fixed/pinned). Justify the material’s selection. verify slenderness and local buckling and Select the lightest section
Design a square tied column to support an axial dead load of (W1) k and an...
Design a square tied column to support an axial dead load of (W1) k and an axial live load of (W2) k. Begin using approximately (X) percent longitudinal steel, a concrete strength of 4,000 psi and Grade 60 steel. Draw the details of reinforcement and check all ACI recommendation. W1 = 220 k W2 = 165 k X = 2%
. Design a square footing for a 16-in. square interior column with an ultimate dead load...
. Design a square footing for a 16-in. square interior column with an ultimate dead load = 300 (k) and an ultimate live load = 200 (k). Take fy=60,000 psi, fc=4000 psi, normal weight, and qa= 4500 psf. Assume the base of the footing is 4 (ft.) below grade. Draw the reinforcement detail also. Check for one way and two way shears with the support of diagram. With ACI code
1) Design a Tied column to support axial Dead load D = 280 K and axial...
1) Design a Tied column to support axial Dead load D = 280 K and axial live load = 500 k, initially assume 2% longitudinal reinforcement f’c = 4000 psi, fy = 60,000 psi. 2) Sketch the column cross-section and show long bars and ties
Q.2. Design a square footing for a 16-in. square interior column with an ultimate dead load...
Q.2. Design a square footing for a 16-in. square interior column with an ultimate dead load = W1 (k) and an ultimate live load = W2 (k). Take fy=60,000 psi, fc=4000 psi, normal weight, and qa= (w) psf. Assume the base of the footing is h (ft.) below grade. Draw the reinforcement detail also. Check for one way and two way shears with the support of diagram.                                                                                                       Student shall take the data given below in the table against...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT