2.00-mol of a monatomic ideal gas goes from State A to State D via the path...

2.00-mol of a monatomic ideal gas goes from State A to State D via the path A?B?C?D:

State A P_A=10.0atm, V_A=12.50L

State B P_B=10.0atm, V_B=7.00L

State C P_C=22.5atm, V_C=7.00L

State D P_D=22.5atm, V_D=21.50L

Assume that the external pressure is constant during each step and equals the final pressure of the gas for that step.

Calculate q for this process.

Calculate w for this process.

Calculate ?E for this process

Calculate ?H for this process.

Solutions

Expert Solution

So, the answers are:

q=90.83 kJ

w = -36.35 kJ

(delta)U = 54.48 kJ

(delta)H = 90.83 kJ

We see that q=delta(H). This is because the process consists of steps of constant pressure and deltaH is defined as heat added at constant pressure.

Amanda K answered 1 year ago

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