In: Other
2.00-mol of a monatomic ideal gas goes from State A to State D via the path A?B?C?D:
State A PA=10.0atm, VA=12.50L |
State B PB=10.0atm, VB=7.00L |
State C PC=22.5atm, VC=7.00L |
State D PD=22.5atm, VD=21.50L |
Assume that the external pressure is constant during each step and equals the final pressure of the gas for that step.
Calculate q for this process.
Calculate w for this process.
Calculate ?E for this process
Calculate ?H for this process.
So, the answers are:
q=90.83 kJ
w = -36.35 kJ
(delta)U = 54.48 kJ
(delta)H = 90.83 kJ
We see that q=delta(H). This is because the process consists of steps of constant pressure and deltaH is defined as heat added at constant pressure.