Question

In: Chemistry

Methylamine, CH3NH2, and methylammonium chloride, CH3NH3Cl write the identity of the two species in each set  (strong...

Methylamine, CH3NH2, and methylammonium chloride, CH3NH3Cl

write the identity of the two species in each set  (strong acid/strong base/weak acid/weak base/salt/other) and explain reason. Identify  if anything in common betweenthe  two species .How are the two species in each set are related to each other?   If there is a weak acid or a weak base present writethe equation for the dissociation of the weak acid or the weak base. Then label the species in theequation as a weak acid and its conjugate base or a weak base and its conjugate acid. Also determine the Ka for the acid species (if you are dealing  with  a  weak base how could you possibly find a Ka  for  the  acid  species  in  the  equation?)Is this mixture a buffer and why?

Solutions

Expert Solution

CH3NH2 is a weak base

CH3NH3Cl is salt

because CH3NH2 + HCl ----------------->CH3NH3Cl

                 base          acid                         salt

CH3NH2 is a base and CH3NH3Cl is conjugate acid. these are base and acid.

CH3NH2 + H2O --------------------->CH3NH3+   +   OH-

base                                            conjugarte acid

Kb of this base = 5.0 x 10^-4

Ka of CH3NH3Cl = Kw / Ka

                           = 1.0 x 10^-14 / 5.0 x 10^-4

                           = 2.0 x 10^-11

the mixture of CH3NH2 + CH3NH3Cl is called buffer


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