In: Physics

A home run is hit in such a way that the baseball just clears a wall 21.0 m high, located 130 m from home plate. The ball is hit at an angle of 35.0° to the horizontal, and air resistance is negligible. Find initial speed of the ball. (Assume the ball is hit at a height of 1.00 m above the ground.)Find the speed of the ball when it reaches the wall.

Since the air resistance is negligible, the x and y components can be calculated separately.

The ball is hit 35° to the horizontal so the relation between the x and y components of the initial velocity is:

tan 35° = vy / vx

vy = vx * tan 35°

vx is constant, but vy changes with time.

?x = 130m

?y = 20m (21m - 1m)

Therefore:

?x = vx*t

?y = vy*t +1/2*g*t²

Plug in known values:

130m = vx*t

vx = 130m / t

Substitute for vy then vx:

20m = vx * tan 35° * t + 1/2 * -9.81m/s² * t²

20m = 130m / t * tan 35° * t + 1/2 * -9.81m/s² * t²

The t cancel out:

20m - 130m*tan 35° = 1/2 * -9.81m/s² * t²

t = ?((20m - 130m*tan 35°) / (1/2 * -9.81m/s²))

t = 3.80532863 s

The ball travels 3.80532863 s before going over the fence

a)

We can use the constant x component of the velocity to calculate the initial velocity.

The relation between the velocity and its x component is:

cos 35° = vx / velocity

vx = dx / t = 130m / 3.80532863 s = 34.1626211 m/s

velocity = vx / cos 35° = 34.1626211 m/s / cos
35° = **41.7048597 m/s**

b)

vx is constant at 34.1626211 m/s

vy can be calculated using the equation:

v = v0 + a*t

Initial vy = 41.7048597 m/s * sin 35° = 23.9209248 m/s

Final vy = 23.9209248 m/s + (-9.81m/s²) * 3.80532863 s Final vy = -13.4093491 m/s

The speed when the ball reaches the wall is (using Pythagorean Theorem):

v = ?(vx² + vy²) = ?((34.1626211 m/s)² + (-13.4093491 m/s)²)

v = **36.7000725
m/s**

A home run is hit in such a way that the baseball just clears a
wall 10 m high, located 128 m from home plate. The ball is hit at
an angle of 37° to the horizontal, and air resistance is
negligible. (Assume that the ball is hit at a height of 1.0 m above
the ground.)
(a) Find the initial speed of the ball.
(b) Find the time it takes the ball to reach the wall.
(c) Find the...

A home run is hit in such a way that the baseball just clears a
wall 14 m high, located 120 m from home plate. The ball is hit at
an angle of 37° to the horizontal, and air resistance is
negligible. (Assume that the ball is hit at a height of 1.0 m above
the ground.)
(a) Find the initial speed of the ball.
-answer in m/s
(b) Find the time it takes the ball to reach the wall....

A home run is hit in such a way that the baseball just clears a
wall 14.0 m high, located 122 m from home plate. The ball is hit at
an angle of 37.0° to the horizontal, and air resistance is
negligible. (Assume that the ball is hit at a height of 1.0 m above
the ground.)
Find the velocity components of the ball when it reaches the
wall.
x - component
y- component

A home run is hit in such a way that the baseball just clears a
wall 14.0 m high, located 128 m from home plate. The ball is hit at
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The following data shows the number of home runs hit by the top
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43 41 39 39 38 37 37
The lower limit for determining outliers for a box and whisker
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The following data shows the number of home runs hit by the top
12 home run hitters in Major League Baseball during the 2011
season.
43 41 39 39 38 37 37 36 34 33 33 32
The lower limit for determining outliers for a box-and-whisker plot
is ________.
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According to the
Guinness Book of World Records,the
longest home run ever measured was hit by Roy

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longest home run ever measured was hit by Roy

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