In: Statistics and Probability
A lot of 106 semiconductor chips contains 29 that are defective. Round your answers to four decimal places (e.g. 98.7654).
a) Two are selected, at random, without replacement, from the lot. Determine the probability that the second chip selected is defective.
b) Three are selected, at random, without replacement, from the lot. Determine the probability that all are defective.
SOLUTION:
From given data,
A lot of 106 semiconductor chips contains 29 that are defective.
Number of chips in a lot =106
Number of defective chips = 29
Suppose two chips are randomly selected without replacement.
Let E1, denote selected chip Is defective in the first selection.
Let E2, denote selected chip Is defective in the second selection.
Also,Ec1 and Ec2 are, compliments of E1 and E2 , respectively,
Probability of selecting a defective chip in the first selection , P( E1) = 29 / 106
If the selected chip is defective in the first selection, then probability of selecting a defective chip in the second selection Is , P( E2 IE1 )=28 / 105,
If the selected chip is defective in the first selection, then probability of selecting a defective chip in the second selection Is , P( E2 IEc1 )=29 / 105,
a) Two are selected, at random, without replacement, from the lot. Determine the probability that the second chip selected is defective.
Probability of selecting, a defective chip in the second selection,
P(E2) = P(E2 E1 ) + P(E2 Ec1 )
= P(E2 | E1 ) P(E1 )+ P(E2 | Ec1 ) P(Ec1)
= (28 / 105)(29 / 106) + (29 / 105)(1-(29 / 106))
= (58 / 795) + (29 / 105)(77/106)
= (58/795)+(319/1590)
= 29/106
= 0.27358
Therefore, probability that the second chip selected is
defective,
P(E2)= 0.27358
b) Three are selected, at random, without replacement, from the lot. Determine the probability that all are defective.
Suppose three chips are randomly selected without replacement.
Compute the probability that all are defective.
P(all are defective) = ( 29 / 106) * (28/105)*(27/104)
= 0.0189
There fore , probability that all are defective is 0.0189