In: Statistics and Probability
For all possible samples of 18 values taken from a population with a mean of −36.33 and a standard deviation of 15.26
P(X(mean) > -33.38)=?
Solution :
Given that ,
mean = = -36.33
standard deviation = = 15.26
n = 18
= = -36.33
and
= / n = 15.26 / 18 = 3.5968
P( > -33.38) = 1 - P( < -33.38 )
= 1 - P(( - ) / < (-33.38 + 36.33) / 3.5968)
= 1 - P(z <0.820 )
= 1 - 0.7939
= 0.2061
Probability = 0.2061