In: Statistics and Probability
For all possible samples of 18 values taken from a population with a mean of −36.33 and a standard deviation of 15.26
P(X(mean) > -33.38)=?
Solution :
Given that ,
mean =
= -36.33
standard deviation =
= 15.26
n = 18
=
= -36.33
and
=
/
n = 15.26 /
18 = 3.5968
P(
> -33.38) = 1 - P(
< -33.38 )
= 1 - P((
-
) /
< (-33.38 + 36.33) / 3.5968)
= 1 - P(z <0.820 )
= 1 - 0.7939
= 0.2061
Probability = 0.2061