Question

In: Chemistry

When a 7.00-g sample of RbBr is dissolved in water in a calorimeter that has a...

When a 7.00-g sample of RbBr is dissolved in water in a calorimeter that has a total heat capacity of 3.090 kJ·K–1, the temperature decreases by 0.300 K. Calculate the molar heat of solution of RbBr.

Solutions

Expert Solution

Heat absorbed by calorimeter = (heat capacity of calorimeter)(Tf - Ti)

                                                    = (3.090 kJ / K)*(0.300 K)

                                                    = 0.927 KJ

molar mass of RbBr = 165.37 g/mole.

moles RbBr = 7.00 g / 165.37 g

                     = 0.0423 moles.

= 0.927 kJ heat / 0.0423 moles RbBr = +21.9 kJ / mole of RbBr

molar heat of solution of RbBr = +21.9 KJ


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