In: Statistics and Probability
The following values are annual car insurance premiums ($) from a 2014 sample of car owners living in Michigan. Use it to answer/do the following. 1905 2725 2677 2600 2962 2184 2332 3112 2545 2525
(a) Estimate the average car insurance premium.
(b) Develop a 90% confidence interval for the mean in (a)
(c) Develop a 95% confidence interval for the mean in (a).
(d) Develop a 99% confidence interval for the mean in (a).
(e) The national average car premium was $1,503 in 2014. Compare this to your answers for (b)-(d). What can you say about car insurance in Michigan?
(a) Average = (1905 + 2725 + 2677 + 2600 + 2962 + 2184 + 2332 + 3112 + 2545 + 2525) / 10 = 2556.7
The sample standard deviation is calculated as 354.74
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(b) 90% CI, = 0.10, and the t critical for df = n - 1 = 9 is 1.833
The Confidence Interval is given by , where
Therefore the 90% CI is 2556.7 205.62
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(c) 95% CI, = 0.05, and the t critical for df = n - 1 = 9 is 2.262
The Confidence Interval is given by , where
Therefore the 95% CI is 2556.7 253.75
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(d) 99% CI, = 0.01, and the t critical for df = n - 1 = 9 is 3.25
The Confidence Interval is given by , where
Therefore the 99% CI is 2556.7 364.58
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(e) The average car insurance in Michigan is greater than the national average of $1503, as none of the above confidene intervals contains the value of $1503.
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