In: Statistics and Probability
The age distribution of the Canadian population and the age distribution of a random sample of 455 residents in the Indian community of a village are shown below.
Age (years) | Percent of Canadian Population | Observed Number in the Village |
Under 5 | 7.2% | 51 |
5 to 14 | 13.6% | 65 |
15 to 64 | 67.1% | 292 |
65 and older | 12.1% | 47 |
Use a 5% level of significance to test the claim that the age distribution of the general Canadian population fits the age distribution of the residents of Red Lake Village.
1 What is the level of significance?
2 State the null and alternate hypotheses.
H0: The distributions are the same.
H1: The distributions are different.H0: The distributions are the same.
H1: The distributions are the same. H0: The distributions are different.
H1: The distributions are different.H0: The distributions are different.
H1: The distributions are the same.
3) Find the value of the chi-square statistic for the sample. (Round your answer to three decimal places.)
4 Are all the expected frequencies greater than 5?
Yes No
5 What sampling distribution will you use?
uniform
Student's t
chi-square
binomial
normal
6 What are the degrees of freedom?
7 Estimate the P-value of the sample test statistic.
P-value > 0.1000
.050 < P-value < 0.100
0.025 < P-value < 0.0500
.010 < P-value < 0.0250
.005 < P-value < 0.010
P-value < 0.005
8 Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?
Since the P-value > α, we fail to reject the null hypothesis.
Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis.
Since the P-value ≤ α, we fail to reject the null hypothesis.
9 Interpret your conclusion in the context of the application.
At the 5% level of significance, the evidence is insufficient to conclude that the village population does not fit the general Canadian population.
At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.
1 What is the level of significance?
0.05
2 State the null and alternate hypotheses.
OPTION a)
H0: The distributions are the same.
H1: The distributions are different.
3) Find the value of the chi-square statistic for the sample. (Round your answer to three decimal places.)
TS = 12.071
4 Are all the expected frequencies greater than 5?
Yes
5 What sampling distribution will you use?
chi-square
6 What are the degrees of freedom?
df = 3
7 Estimate the P-value of the sample test statistic.
p-value =
0.007144 |
.005 < P-value < 0.010
8 Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?
Since the P-value ≤ α, we reject the null hypothesis.
9 Interpret your conclusion in the context of the application.
At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.