Question

In: Statistics and Probability

The age distribution of the Canadian population and the age distribution of a random sample of...

The age distribution of the Canadian population and the age distribution of a random sample of 455 residents in the Indian community of a village are shown below.

Age (years) Percent of Canadian Population Observed Number
in the Village
Under 5 7.2%                   45            
5 to 14 13.6%                   72            
15 to 64 67.1%                   291            
65 and older 12.1%                   47            

Use a 5% level of significance to test the claim that the age distribution of the general Canadian population fits the age distribution of the residents of Red Lake Village.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: The distributions are different.
H1: The distributions are different.

H0: The distributions are the same.
H1: The distributions are different.     

H0: The distributions are the same.
H1: The distributions are the same.

H0: The distributions are different.
H1: The distributions are the same.


(b) Find the value of the chi-square statistic for the sample. (Round your answer to three decimal places.)


Are all the expected frequencies greater than 5?

Yes

No     


What sampling distribution will you use?

chi-square

uniform     

binomial

Student's t

normal


What are the degrees of freedom?


(c) Estimate the P-value of the sample test statistic.

P-value > 0.100

0.050 < P-value < 0.100     

0.025 < P-value < 0.050

0.010 < P-value < 0.025

0.005 < P-value < 0.010

P-value < 0.005


(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?

Since the P-value > α, we fail to reject the null hypothesis.

Since the P-value > α, we reject the null hypothesis.     

Since the P-value ≤ α, we reject the null hypothesis.

Since the P-value ≤ α, we fail to reject the null hypothesis.


(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, the evidence is insufficient to conclude that the village population does not fit the general Canadian population.

At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.















Solutions

Expert Solution

(a)

The level of significance = = 0.05

Correct option:

H0:The distributions are same.

H1: The distributions are different.

(b)

The test statistic is calculated as follows:

Age (years) Observed Frequency (O) Expected Frequency (E) (O - E)2/E
Under 5 45 455X7.2/100=32.76 4.573
5 to 14 72 455X13.6/100=61.88 1.655
15 to 64 291 455X67.1/100=305.31 0.670
65 and above 47 455X12.1/100=55.06 1.178
Total = = 8.076

Chi square statistic = 8.076

Correct option:

Yes

Correct option:

Chi square

Degrees of freedom = n - 1=4 - 1 = 3

(c)
By Technology, p - value = 0.0445

So,

Correct option:

0.025 < p value< 0.050

(d)

Correct option:

Since p -value , we reject the null hypothesis

(e)

Correct option:

At the 5% level of significance, the evidence is sufficient to conclude that the village population does not fit the general Canadian population.


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