In: Chemistry
The pH of a 0.392 M solution of the conjugate base, A-, of a weak acid, HA, is 11.60. What is the Kb for A-?
Please show work
pH = 11.60
[ A- ] = 0.392 M
[H+] = 10^-pH
= 10^-11.60
= 2.5 x 10^-12 M
[OH-] = 1.0 x 10^-14 / 2.5 x 10^-12 = 4 x 10^-3 M
A- + H2O ---------------------> AH + OH-
0.392 0 0
0.392-x x x
x = [OH-] = 4 x 10^-3 M
Kb = x^2 / 0.392 -x
kb = (4 x 10^-3)^2 / (0.392 - 4 x 10^-3)
Kb = 4.12 x 10^-5