Question

Using the Capacitor Lab simulation, you will explore the factors that affect the capacitance of a parallel plate capacitor.

Start the Capacitor Lab simulation. Play with the simulation to get familiar with the options provided. When ready to start the lab, click “Reset All.” You should be on the “Introduction” tab. Slide the button on the battery to 1.5 V. Select all meters except Voltmeter and Electric field Detector. Make sure both Plate Charge and Electric Field Lines button are checked. Increase the plate area for the capacitor by clicking and dragging the green arrow for “Plate area.”

Here is the link:

https://phet.colorado.edu/en/simulation/legacy/capacitor-lab

32.

What happens to the capacitance when the plate area is increased?

A. The capacitance is increasing.

B. The capacitance is not changing.

C. The capacitance is decreasing.

33.

What happens to the charge on the capacitor when the plate area is increased?

A. The charge on the parallel plates is increasing.

B. The charge on the parallel plates is not changing.

C. The charge on the parallel plates is decreasing.

34.

What happens to the voltage across the capacitor when the plate area is increased?

A. The voltage across the capacitor is increasing.

B. The voltage across the capacitor stays the same.

C. The voltage across the capacitor is decreasing.

Make sure the voltage of the battery is set at 1.5 V, the separation between plates is 10 mm and the plate area is 100 mm². Now decrease the separation between the plates.

35.

What happens to the capacitance when the separation between the plates is decreased?

A. The capacitance is increasing.

B. The capacitance is not changing.

C. The capacitance is decreasing.

36.

What happens to the charge on the capacitor when the separation between the plates is decreased?

A. The charge on the parallel plates is increasing.

B. The charge on the parallel plates is not changing.

C. The charge on the parallel plates is decreasing

37.

What happens to the voltage across the capacitor when the separation between the plates is decreased?

A. The voltage across the capacitor is increasing.

B. The voltage across the capacitor stays the same.

C. The voltage across the capacitor is decreasing.

Set the separation to 10 mm and plate area to 100 mm2. Disconnect the battery by clicking “Disconnect battery.” Increase the plate area for the capacitor.

38.

What happens to the capacitance when the plate area is increased?

A. The capacitance is increasing.

B. The capacitance is not changing.

C. The capacitance is decreasing.

39.

What happens to the charge on the capacitor when the plate area is increased?

A. The charge on the parallel plates is increasing.

B. The charge on the parallel plates is not changing.

C. The charge on the parallel plates is decreasing

40.

What happens to the voltage across the capacitor when the plate area is increased?

A. The voltage across the capacitor is increasing.

B. The voltage across the capacitor stays the same.

C. The voltage across the capacitor is decreasing.

Thank you!!

Answer 1

the parallel plate capacitor

the capacitance is C = epsolon not*A/d

A is area of the plates and d is separation of the plates

32.

What happens to the capacitance when the plate area is increased?

if area increased the capacitance also increased

C1/C2 = A1/A2

C2 = C1*A2/A1

if A2 >A1 then C2 > C1

A. The capacitance is increasing.

33.

What happens to the charge on the capacitor when the plate area is increased?

from relation Q = C*V

if Q increased if Area increases because the capacitance increases

the answer is A. The charge on the parallel plates is increasing.

34.

What happens to the voltage across the capacitor when the plate area is increased?

Q = c*v

c and V are inversly proportional to each other if A increases the C will also increases there by the voltage across the capacitor decreases

C.The voltage across the capacitor is decreasing.

35. What happens to the capacitance when the separation between the plates is decreased?

Ans

A. The capacitance is increasing. because the capacitance is C = epsolon not*A/d  

36. What happens to the charge on the capacitor when the separation between the plates is decreased?

B. The charge on the parallel plates is not changing.

37. What happens to the voltage across the capacitor when the separation between the plates is decreased?

C.The voltage across the capacitor is decreasing. if the charge is same