In: Chemistry
Consider the table of data collected for the reaction A Products. Determine the magnitude (value) of the reaction rate constant by graphing the data appropriately.
Given reaction is A ----> Products
Rate=k[A]x
where k=rate constant, x=order of reaction.
The rate laws are
The zero-order rate law is [A]=-kt+[A]0
If the plot of [A] vs time gives a straight line then the order of the reaction is zero-order and the slope of the line is equal to rate constant.
First-order rate law is ln[A]=-kt+ln[A]0
If the plot of ln [A] vs time gives a straight line then the order of the reaction is first-order and the slope of the line is equal to rate constant.
The second-order rate law is 1/[A]=kt+1/[A]0
If the plot of 1/[A] vs time gives a straight line then the order of the reaction is second-order and the slope of the line is equal to rate constant.
Where [A]0=initial concentration of A,
k=rate constant and [A]=concentration of A at time t.
The calculations are shown below the table
Time(s) | [A](M) | ln[[A] | 1/[A] |
0 | 0.75 | -0.287682072 | 1.333333333 |
0.5 | 0.665 | -0.407968238 | 1.503759398 |
1 | 0.575 | -0.553385238 | 1.739130435 |
1.5 | 0.49 | -0.713349888 | 2.040816327 |
2 | 0.41 | -0.891598119 | 2.43902439 |
2.5 | 0.32 | -1.139434283 | 3.125 |
3 | 0.235 | -1.448169765 | 4.255319149 |
3.5 | 0.15 | -1.897119985 | 6.666666667 |
4 | 0.06 | -2.813410717 | 16.66666667 |
The Zero-order plot is
The first order plot is
The second-order plot is
From the above plots, the plot [A] vs time gives a straight line with R2=0.9999.
Therefore the order of the reaction is zero order.
The rate law is
Rate=k[A]0
Rate=k
The slope of the line=-k=-0.17183 M s-1.
rate constant=k=0.172 M s-1.
Please let me know if you have any doubt. Thanks