In: Chemistry
Using the data in the table, determine the rate constant of the reaction and select the appropriate units.
A+2B⟶C+D
Trial | [A] (M)[A] (M) | [B] (M)[B] (M) | Rate (M/s) |
---|---|---|---|
1 | 0.3900.390 | 0.3800.380 | 0.01730.0173 |
2 | 0.3900.390 | 0.7600.760 | 0.01730.0173 |
3 | 0.7800.780 | 0.3800.380 | 0.06920.0692 |
k=
Units
M−1s−1
see experiment 1 and 3:
[A] doubles
[B] is constant
rate becomes 4 times
so, order of A is 2
see experiment 1 and 2:
[A] is constant
[B] doubles
rate is constant
so, order of B is 0
overall order = 2 + 0 = 2
Rate law is:
rate = k*[A]^2
Put values from 1st row of table in rate law
rate = k*[A]^2
1.73*10^-2 = k*0.39^2*0.38^0
k = 0.1137 M-1.s-1
Answer: 0.114 M-1.s-1