Question

(Java Zybooks) Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn cat.", then output is:

Censored

Ex: If userInput is "Dang, that was scary!", then output is:

Dang, that was scary!

Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.

import java.util.Scanner;

public class CensoredWords {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
String userInput;

userInput = scnr.nextLine();

/* Your solution goes here */

}
}

Answer 1

Note: The modified part of the code is highlighted in grey and bold.

Screenshot of the code:

Sample Output:

Code to copy:

//Import required package.

import java.util.Scanner;

//Define the class CensoredWords.

public class CensoredWords

{

//Start the main() method.

public static void main (String [] args)

{

    //Create an object of the class Scanner class.

    Scanner scnr = new Scanner(System.in);

    //Declare required variables.

    String userInput;

    //Prompt the user to input a string.

    userInput = scnr.nextLine();

    /* Your solution goes here */

    //Find the index of string darn in the string

    //userInput using the method indexOf(). If the

    //returned value is not -1, then it means that

    //the word darn is included in the string and

    //display censored.

    if(userInput.indexOf("darn") != -1)

    {

      System.out.println("Censored");

    }

   

    //Otherwise, display the string userInput with

    //newline.

    else

    {

      System.out.println(userInput);

    }

}

}