Question

Print "Censored" if userInput contains the word "darn", else print userInput. End with newline. Ex: If userInput is "That darn cat.", then output is:

Censored

Ex: If userInput is "Dang, that was scary!", then output is:

Dang, that was scary!

Note: If the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message.

#include <iostream>
#include <string>
using namespace std;

int main() {
string userInput;

getline(cin, userInput);

int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl; /* Your solution goes here */

return 0;
}

Answer 1

#include <iostream>
#include <string>

using namespace std;

int main() {
    string userInput;

    getline(cin, userInput);

    int isPresent = userInput.find("darn");
    if (isPresent >= 0) {
        cout << "Censored" << endl;
    } else {
        cout << userInput << endl;
    }
    return 0;
}