In: Chemistry
This would undergo what is called radical halogenation. The product would be 2-bromo-2,4-dimethylpentane. The heat causes the sigma bond in the bromine molecule to split and form two bromine radicals. One of these bromine radical will perform a radical hydrogen abstraction of the hydrogen atom at the 2-position of 2,4-dimethylpentane and form a tertiary radical. This alkyl radical will then either react with the other bromine radical or another bromine molecule to form the product. I hope this helps!
Photoinduced bromination of 2,4-dimethylpentane can give three different products having a single bromo substituent. The relative amounts of each is according to the relative reactivity of 3° > 2° > 1° hydrogens and the product formed is in the ratio of 1:82:1640.