Question

In: Statistics and Probability

The upper leg length of 20 to 29 year olds males is normally distributed with mean...

  1. The upper leg length of 20 to 29 year olds males is normally distributed with mean length of 43.7 cm and a standard deviation of 4.2 cm
    1. What is the probability that a randomly selected 20-29 year old male has an upper leg length of that is less than 40 cm?
    2. Suppose a random sample of 9 males who are 20-29 years old is obtained. What is the probability that their mean leg length is less than 40 cm?
    3. A random sample of 15 males who are 20-29 years old results in a mean leg length of 46 cm or more. Do you find this result unusual? Why?

  1. The reading rates of second grade students is approximately normal with a mean of 90 words per minute and a standard deviation of 10 words per minute
    1. What is the probability that a random student will read more than 95 words per minute?
    2. What is the probability that a random sample of 24 second grade students will result a mean reading rate of more than 95 words per minute?
    3. A teacher initiated a new reading program at school. After 10 weeks on the program, it was found that the mean reading speed of a random sample of 20 second grade students was 93 words per minute? Is this result unusual? What does this suggest about the effectiveness of the program?

Solutions

Expert Solution

1)a)

for normal distribution z score =(X-μ)/σ
here mean=       μ= 43.7
std deviation   =σ= 4.2000
probability = P(X<40) = P(Z<-0.88)= 0.1894

b)

sample size       =n= 9
std error=σ=σ/√n= 1.4000
probability = P(X<40) = P(Z<-2.64)= 0.0041

c)

sample size       =n= 15
std error=σ=σ/√n= 1.0844
probability = P(X>46) = P(Z>2.12)= 1-P(Z<2.12)= 1-0.9830= 0.0170

2)

for normal distribution z score =(X-μ)/σ
here mean=       μ= 90
std deviation   =σ= 10.0000
probability = P(X>95) = P(Z>0.5)= 1-P(Z<0.5)= 1-0.6915= 0.3085

b)

sample size       =n= 24
std error=σ=σ/√n= 2.0412
probability = P(X>95) = P(Z>2.45)= 1-P(Z<2.45)= 1-0.9929= 0.0071

c)

sample size       =n= 20
std error=σ=σ/√n= 2.2361
probability = P(X>93) = P(Z>1.34)= 1-P(Z<1.34)= 1-0.9099= 0.0901

as probability of that happening is not less than 0.05 level ; therefore it is not unusual.


Related Solutions

The waist circumference of males 20-29 years old is approximately normally distributed, with mean 92.5 cm...
The waist circumference of males 20-29 years old is approximately normally distributed, with mean 92.5 cm and standard deviation 13.7 cm. (a) Use the normal model to determine the proportion of 20- to 29-year-old males whose waist circumference is less than 100 cm. (b) What is the probability that a randomly selected 20- to 29-year-old male has a waist circumference between 80 and 100 cm? (c) Determine the waist circumferences that represent the middle 90% of all waist circumferences. Please...
The waist circumference of males 20-29 years old is approximately normally distributed, with mean 36.4 inches...
The waist circumference of males 20-29 years old is approximately normally distributed, with mean 36.4 inches and standard deviation of 5.4. a.Determine the proportion of 20-29 year old males whose waist circumference is greater than 39.4 in. You must show your work and/or give supporting evidence in order to receive credit.Round the proportion to four decimal places. b.Determine the waist circumference that is at the 10th percentile. You must show your work and/or give supporting evidence in order to receive...
The height of women (ages 20 to 29) are approximaltely normally distributed with a mean of...
The height of women (ages 20 to 29) are approximaltely normally distributed with a mean of 68 inches and standard deviation of 3.8 inches. The heights of men (ages 20 to 29) are approximately normally distributed with a mean height of 71.5 inches and a standard deviation of 3.4 inches. A) Use the z- score to compare a woman that is 5 feet 7 inches and a man that is 5 feet 7 inches tall. B) If a z-score of...
1.) Suppose heights of two-year-olds are normally distributed with a mean of 30 inches and a...
1.) Suppose heights of two-year-olds are normally distributed with a mean of 30 inches and a standard deviation of 3.5 inches. a) What is the probability that one two-year-old will be shorter than 28 inches? b) If random samples of size n = 40 two-year-olds are selected, what is the approximate shape, mean, and standard deviation of the sampling distribution of sample means? c) What is the probability that the sample mean of these 40 two-year-olds will be shorter than...
The height of women ages​ 20-29 are normally​ distributed, with a mean of 64.3 inches. Assume...
The height of women ages​ 20-29 are normally​ distributed, with a mean of 64.3 inches. Assume sigmaequals2.5 inches. Are you more likely to randomly select 1 woman with a height less than 66.2 inches or are you more likely to select a sample of 18 women with a mean height less than 66.2 ​inches? Explain. What is the probability of randomly selecting 1 woman with a height of less than 66.2 ​inches? _______​(Round to four decimal places as​ needed.) What...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.2 inches. Assume...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.2 inches. Assume sigmaequals2.9 inches. Are you more likely to randomly select 1 woman with a height less than 65.3 inches or are you more likely to select a sample of 29 women with a mean height less than 65.3 ​inches? Explain. LOADING... Click the icon to view page 1 of the standard normal table. LOADING... Click the icon to view page 2 of the standard normal...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.7 inches. Assume...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.7 inches. Assume sigmaσequals=2.7 inches. Are you more likely to randomly select 1 woman with a height less than 67.267.2 inches or are you more likely to select a sample of 10 women with a mean height less than 67.2 ​inches? Explain. LOADING... Click the icon to view page 1 of the standard normal table. LOADING... Click the icon to view page 2 of the standard normal...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.2 inches. Assume...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.2 inches. Assume σ=2.7 inches. Are you more likely to randomly select 1 woman with a height less than 66.3 inches or are you more likely to select a sample of 14 women with a mean height less than 66.3​inches? Explain.
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.4 inches. Assume...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 64.4 inches. Assume sigma = 2.6 inches. Are you more likely to randomly select 1 woman with a height less than 65.8 inches or are you more likely to select a sample of 22 women with a mean height less than 65.8 ​inches? Explain. What is the probability of randomly selecting 1 woman with a height less than 65.8 ​inches? What is the probability of selecting a...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 63.6 inches. Assume...
The height of women ages​ 20-29 is normally​ distributed, with a mean of 63.6 inches. Assume sigma σ equals = 2.6 inches. Are you more likely to randomly select 1 woman with a height less than 65.2 inches or are you more likely to select a sample of 18 women with a mean height less than 65.2 ​inches? Explain.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT