Question

1. A nursing audit was carried out for four populations of patients in a large community hospital. The total audit score for each patient reflects nursing performance for several basic areas (application of nursing procedures and promotion of total health, for example). The table below presents the total audit scores for five randomly selected patients on within each of the audited populations within the given hospital.

   Medical	Surgical	Pediatrics	Ob-Gyn
   75	75	70	50
   65	80	70	65
   50	85	60	70
   60	70	75	70
   70	90	80	75

   The sample means: 64    80 71    66

   Sample st deviations:         9.62 7.91 7.42    9.62

   Perform analysis of variance on this data. The F-statistic for the ANOVA test, rounded to three decimal places, is

1 points   

QUESTION 8

1. The P-value for the ANOVA test in number 7 is

   	A.	between 0.05 and 0.10.
   	B.	greater than 0.10.
   	C.	less than 0.01.
   	D.	less than 0.05.

1 points   

QUESTION 9

1. Which one of the statements below is the best conclusion for your test in number 7?

   	A.	The test shows that the differences in the mean scores are statistically significant but in looking at the descriptive summaries (sample means) we see that the differences are not practically significant.
   	B.	The test shows that the differences in mean scores are not statistically significant.
   	C.	The test allows us to conclude that the mean scores are not all the same, and descriptive summaries of the data (sample means) suggest the mean score for surgical nursing performance is highest.
   	D.	The test allows us to conclude that the mean scores are not all the same, but the mean scores for medical and Ob-Gyn patients are the same.

1 points   

QUESTION 10

1. The ANOVA test of the data in #7 is better than comparing the four populations of scores in six different two-sample tests (comparing all possible pairs) because

   	A.	the conclusions from the six two-sample procedures might not agree.
   	B.	the two-sample tests can be one-sided or two sided and we don't know which alternatives are best.
   	C.	we can control the probability of making a type I error with a single ANOVA test but not with six separate tests, each of which could result in a Type I error.
   	D.	the conditions for two-sample procedures might not be met for all 6 pairs of scores.

Answer 1

Sol:

Perform one way ANOVA in excel

Data >Data analysis>single factor ANOVA

you will get

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
Medical	5	320	64	92.5
Surgical	5	400	80	62.5
Pediatrics	5	355	71	55
Ob-Gyn	5	330	66	92.5
ANOVA
Source of Variation	SS	df	MS	F	P-value	F crit
Between Groups	763.75	3	254.5833	3.366391	0.044836	3.238872
Within Groups	1210	16	75.625
Total	1973.75	19

The F-statistic for the ANOVA test, rounded to three decimal places, is

F=3.366

QUESTION 8

P value=0.0448

MARK OPTION

less than 0.05.

Solution9:

p<0.05

Reject Ho

Accept Ha

atleast one of the group means are different.

Groups	Average
Medical	64
Surgical	80
Pediatrics	71
Ob-Gyn	66

The test allows us to conclude that the mean scores are not all the same, and descriptive summaries of the data (sample means) suggest the mean score for surgical nursing performance is highest.