In: Chemistry
A pH 3.30 buffer is prepared from iodoacetic acid ICH2COOH (pKa = 3.175), and sodium iodoacetate, ICH2COO-Na+ . If ionic strength of the buffer solution must not exceed 0.200 M, what are the maximum concentrations of the two components that could be used?
What volume of KOH (conc = 1.850 M), could be added to 50.00 mL of the buffer solution of part (a), before the pH would increase to 4.000?
ICH2COONa + ICH2COOH = 0.200 M
pH = pKa + log [salt/acid]
3.30 = 3.175 + log (ICH2COONa/ICH2COOH)
1.33 = ICH2COONa / ICH2COOH
ICH2COONa + ICH2COOH = 0.200 M
1.33 ICH2COOH + ICH2COOH = 0.200
2.33 ICH2COOH = 0.200
[ICH2COOH] = 0.0858 M
ICH2COONa = 1.33 ICH2COOH = 1.33 x 0.0858
= 0.114 M
[ICH2COONa] = 0.114 M
ICH2COOH + KOH -------------------> ICH2COOK + H2O
0.0858 x 50 1.850 V 0 0
4.29 - 1.850 V 0 1.850 V 1.850V
here salt and acid remaining so it forms acidic buffer.
pH = pKa + log [salt / acid]
4.00 = 3.175 + log [1.850V / 4.29 - 1.850V]
6.68 = [1.850V / 4.29 - 1.850V]
V = 2.02 mL
volume of KOH added = 2.02 mL