Question

In: Computer Science

Write function boolean isSorted(int a[], int size). The function returns true if array a is sorted...

Write function boolean isSorted(int a[], int size). The function returns true if array a is sorted in either ascend order or descend order; false otherwise.

c++

Solutions

Expert Solution

Please follow the below code with inline comments:

bool isSorted(int a[],int size){
int temp[size-1];
bool result = true;
for(int i=0;i<size;i++)
temp[i]=a[i];
sort(a, a+size);//using in build function for sorting the array.
for(int i=0;i<size;i++){// checking whether array in sorted in ascending order or not
if(a[i]!=temp[i])
{
result = false;break;
}
}
int j=size-1;
for(int i=0;i<size;i++){// checking array is in descending order or not
if(a[i]!=temp[j++])
{
result = false;break;
}
}
return result;
}

The full program to test the function is below:

#include <bits/stdc++.h>
#include <iostream>

using namespace std;

bool isSorted(int a[],int size){
int temp[size-1];
bool result = true;
for(int i=0;i<size;i++)
temp[i]=a[i];
sort(a, a+size);//using in build function for sorting the array.
for(int i=0;i<size;i++){// checking whether array in sorted in ascending order or not
if(a[i]!=temp[i])
{
result = false;break;
}
}
int j=size-1;
for(int i=0;i<size;i++){// checking array is in descending order or not
if(a[i]!=temp[j++])
{
result = false;break;
}
}
return result;
}

int main()
{
int arr[]={1,2,4,5};
int size = 4;
bool result = isSorted(arr,size);
cout <<"\n"<< result;
return 0;
}

Output:

0 means false

1 means true.


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