Question

In this exercise, we will investigate the chemical potential μμ upon a change in volume. We will use the fact that F=U−TSF=U−TS and μ=∂F/∂N. We will compute μ(Vf)−μ(Vi)μ(Vf)−μ(Vi)

In all questions, take N=20 moles (which is 20 times Avagodro's number of particles), T=300 K, V_i=0.01 m³,V_f=0.02 m³

1) For a gas with an excluded volume:

• U=3/2NkT+const
• S=Nkln(V−bN)+const

If bb=10^-28 m³, compute μ(Vf)−μ(Vi)

2.) For a gas with an excluded volume and attraction between the particles:

• U=3/2NkT−aN^2/V+const
• S=Nkln(V−bN)+const

If aa=10^-49 m³ and bb=10^-28 m³, compute μ(Vf)−μ(Vi)

Answer 1