As indicated in the following figure, an incompressible silty sand fill 16.4 ft thick was placed...

As indicated in the following figure, an incompressible silty sand fill 16.4 ft thick was
placed on top of a 49.2 ft thick layer of soft and compressible silty clay. Underlying the
clay is a layer of incompressible sandy gravel. The soil properties of the silty clay layer are
given in the following figure. The ultimate settlement, Sult = 5.64 ft, from the primary
consolidation of silty clay layer due to the weight of the silty sand fill is calculated.

A) the time rate of settlement by showing the Time [year] vs. Settlement [ft] curve.
Show sample calculation when percentage of consolidation, Uavg = 50% to receive full
credits!

the time rate of settlement by showing the Time [year] vs. Settlement [ft] curve.
Show sample calculation when percentage of consolidation, Uavg = 50% to receive full
credits!
γ = 94.89 pcf
eo = 1.1
Cc = 0.36
Cα= 0.06
cv = 9.235 ft2
/year
Fill Material - Silty Sand
(SM), γ = 124.86 pcf,
Dense Sandy Gravel (GP),
Incompressible layer
16.4 ft
0 ft

Expert Solution

U	T_v (when U<=60%)	T_v (When U>60%)	t	St
0	0.0000	-	0.00	0.000
5	0.0020	-	0.13	0.282
10	0.0079	-	0.51	0.564
15	0.0177	-	1.16	0.846
20	0.0314	-	2.06	1.128
25	0.0491	-	3.22	1.410
30	0.0707	-	4.63	1.692
35	0.0962	-	6.30	1.974
40	0.1257	-	8.23	2.256
45	0.1590	-	10.42	2.538
50	0.1963	-	12.87	2.820
55	0.2376	-	15.57	3.102
60	0.2827	-	18.53	3.384
65	-	0.3404	22.31	3.666
70	-	0.4028	26.40	3.948
75	-	0.4767	31.24	4.230
80	-	0.5671	37.16	4.512
85	-	0.6837	44.80	4.794
90	-	0.8480	55.57	5.076
92	-	0.9384	61.49	5.189
94	-	1.0550	69.13	5.302
96		1.2193	79.90	5.414
97		1.3358	87.54	5.471
98		1.5001	98.30	5.527
99		1.7810	116.71	5.584

[In the above table Tv for U<60% is calculated using equation (3) and Tv for U> 60% is calculated using equation (4)]

Ally Wells answered 2 years ago

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