In: Math
A researcher is interested in determining if the attitude about homosexual marriages is dependent on region. In order to do the Chi-Square association test, she ran analysis with Minitab and came up with the contingency table that summarizes the actual observations and the expected observations. α=0.05.
| Agree | Disagree | Neutral | |
| East | 78 | 136 | 16 | 
| Midwest | 63 | 183 | 16 | 
| South | 74 | 23 | 16 | 
| West | 50 | 138 | 7 | 
Report your test statistic and your conclusion .
Round your test statistic to the nearest decimal. Report your conclusion as D (dependent) or I (independent)
Chi-square test of independence
Solution:
Here, we have to use chi square test for independence of two categorical variables.
Null hypothesis: H0: The attitude about homosexual marriages is independent on region.
Alternative hypothesis: Ha: The attitude about homosexual marriages is dependent on region.
We are given level of significance = α = 0.05
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
E = row total * column total / Grand total
We are given
Number of rows = r = 4
Number of columns = c = 3
Degrees of freedom = df = (r – 1)*(c – 1) = 3*2 = 6
α = 0.05
Critical value = 12.59159
(by using Minitab)
Calculation tables for test statistic are given as below:
| 
 Observed Frequencies  | 
||||
| 
 Column variable  | 
||||
| 
 Row variable  | 
 Agree  | 
 Disagree  | 
 Neutral  | 
 Total  | 
| 
 East  | 
 78  | 
 136  | 
 16  | 
 230  | 
| 
 Midwest  | 
 63  | 
 183  | 
 16  | 
 262  | 
| 
 South  | 
 74  | 
 23  | 
 16  | 
 113  | 
| 
 West  | 
 50  | 
 138  | 
 7  | 
 195  | 
| 
 Total  | 
 265  | 
 480  | 
 55  | 
 800  | 
| 
 Expected Frequencies  | 
||||
| 
 Column variable  | 
||||
| 
 Row variable  | 
 Agree  | 
 Disagree  | 
 Neutral  | 
 Total  | 
| 
 East  | 
 76.1875  | 
 138  | 
 15.8125  | 
 230  | 
| 
 Midwest  | 
 86.7875  | 
 157.2  | 
 18.0125  | 
 262  | 
| 
 South  | 
 37.43125  | 
 67.8  | 
 7.76875  | 
 113  | 
| 
 West  | 
 64.59375  | 
 117  | 
 13.40625  | 
 195  | 
| 
 Total  | 
 265  | 
 480  | 
 55  | 
 800  | 
| 
 Calculations  | 
||
| 
 (O - E)  | 
||
| 
 1.8125  | 
 -2  | 
 0.1875  | 
| 
 -23.7875  | 
 25.8  | 
 -2.0125  | 
| 
 36.56875  | 
 -44.8  | 
 8.23125  | 
| 
 -14.5938  | 
 21  | 
 -6.40625  | 
| 
 (O - E)^2/E  | 
||
| 
 0.043119  | 
 0.028986  | 
 0.002223  | 
| 
 6.519892  | 
 4.234351  | 
 0.224853  | 
| 
 35.72612  | 
 29.60236  | 
 8.721284  | 
| 
 3.297185  | 
 3.769231  | 
 3.061262  | 
Chi square = ∑[(O – E)^2/E] = 95.23087
P-value = 2.48E-18 = 0.00
(By using Minitab)
P-value < α = 0.05
So, we reject the null hypothesis
There is sufficient evidence to conclude that the attitude about homosexual marriages is dependent on region.
Conclusion: D