You have 0.4mL of acetic acid and 0.4mL of isoamyl alcohol for the experiment. Which is...

You have 0.4mL of acetic acid and 0.4mL of isoamyl alcohol for the experiment. Which is the limiting reactant?

Expert Solution

acetic acid mass = volume x density

= 0.4 ml x 1.05 g/ml

= 0.42 g

acetic acid moles = mass / Molar mass of acetic acid

= 0.42 g / ( 60.05 g/mol) = 0.007

isoamyl alcohol mass = vol x density

= 0.4 ml x 0.81 g/ml =0.324 g

isoamyl alcohol moles = mass / molar mass of it

= 0.324 g / 88 g/mol

= 0.0037

acetic acid and isoamyl alcohol react in 1:1 ratio

since relatively isoamyl alcohol is less the liming reagent is isoamyl alcohol

( densities and molar mass values taken from web)

queen_honey_blossom answered 1 year ago

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