If a solution containing 39.142 g39.142 g of mercury(II) nitrate is allowed to react completely with...

If a solution containing 39.142 g39.142 g of mercury(II) nitrate is allowed to react completely with a solution containing 10.872 g10.872 g of sodium dichromate, how many grams of solid precipitate will form?

precipitate:

How many grams of the reactant in excess will remain after the reaction?

excess reactant:

Expert Solution

16.67 grams of solid precipitate of HgCr₂O₇ will be produced.

After the complete reaction 25.98 grams of Hg(NO₃)₂ will be in excess.

The detail calculation is shown below.

queen_honey_blossom answered 1 year ago

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