Question

1.) Write a function, base2tobase10 that has a single input, a vector containing 1,s and 0 's representing a binary number. For example the binary number 01101011 would be represented by the vector [ 0, 1, 1, 0, 1, 0,1, 1]. Your function should return a single output,the base 10 equivalent of the base 2 number.

First, your function must check the input vector and detremine if any of the vector elemnets are not a 0 or a1. If they are not, print error message "Please enter only ones and 0's" using fprintf() and exit gracefully to the console prompt using "return"

Reall that in Base 10

mySum = 4+70+300+2000+10000

So , in base 2

MySum = 1+2+0+8+0+32+64+0

Test code DO NOT CHANGE ANY OF THIS CODE

score = 0;

% -------------TEST base2tobase10 ------------------

rng(123456);

myBin = [ 1 1 0 1 1];

try

myBase10 = base2tobase10(myBin);

catch

warning('Problem using function. Assigning a value of 0.');

myBase10 = 0

end

if myBase10 == bin2dec(num2str(myBin))

fprintf('first test of base2tobase10 passed')

else

fprintf('first test of base2tobase10 failed')

end

myBin = [1];

try

myBase10 = base2tobase10(myBin);

catch

warning('Problem using function. Assigning a value of 0.');

myBase10 = 0

end

if myBase10 == bin2dec(num2str(myBin))

fprintf('second test of base2tobase10 passed')

else

fprintf('second test of base2tobase10 failed')

end

1. base2tobase10 .

insert your code in the box below

%insert your code here

Answer 1

Please find the answer below.
Please do comments in case of any issue. Also, don't forget to rate the question. Thank You So Much.

Function First

base2tobase10.m

function res = base2tobase10( v )
res = 0;
for k=length(v):-1:1
res = res + power(2,k-1)*v(k);
end
end

Main.m

clc
clear
rng(123456);

myBin = [ 1 1 0 1 1];

try
  
myBase10 = base2tobase10(myBin);
  
catch
  
warning('Problem using function. Assigning a value of 0.');
  
myBase10 = 0;
  
end

if myBase10 == bin2dec(num2str(myBin))
  
fprintf('first test of base2tobase10 passed')
  
else
  
fprintf('first test of base2tobase10 failed')
  
end

myBin = [1];
fprintf("\n");
try
  
myBase10 = base2tobase10(myBin);
  
catch
  
warning('Problem using function. Assigning a value of 0.');
  
myBase10 = 0;
  
end

if myBase10 == bin2dec(num2str(myBin))
  
fprintf('second test of base2tobase10 passed')
  
else
  
fprintf('second test of base2tobase10 failed')
  
end

output