Question

Often we would like to make the user think we like him/her so we use a friendly prompt to get them to decide if they want to continue a loop. One can make a sentinel using an integer value outside of the expected input range but a more delightful way is to ask politely if: System.out.println("Do you want to play again?);

In order to do this we will need a scanner and a do-while loop. For the scanner sometimes the compiler seems to malfunction if the same scanner object is used for different data types so I prefer to use 2 scanner object- one for numbers and one for strings, rather than one object with a wrapper/parser.

So set up: Scanner again = new Scanner(system.in);

String another="";

do {

//whatever stuff you want to do like an inner loop to play a game like Hi-Lo

System.out.println("Do you want to play again?);

another=again.nextLine();

}

while(another.equalsIgnoreCase("yes") || another.equalsIgnoreCase("y"));

This is Java Please

Answer 1

import java.util.Scanner;

public class Prompt {
        public static void main(String[] args) {
                Scanner again = new Scanner(System.in);
                Scanner sc = new Scanner(System.in);
                String another = "";

                do {
                        System.out.println("Heads-1 or Tails - 0?");
                        int ch = sc.nextInt();
                        int x = (int) (System.currentTimeMillis() % 2);
                        if (x == ch) {
                                System.out.println("You won toss");
                        } else {
                                System.out.println("You lost toss");
                        }
                        System.out.println("Do you want to play again?");

                        another = again.nextLine();

                }

                while (another.equalsIgnoreCase("yes") || another.equalsIgnoreCase("y"));
        }
}

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