Question

In: Statistics and Probability

perform the appropraite test of hypothesis with minitab. Null hypothesis: mean of the post scores is...

perform the appropraite test of hypothesis with minitab.
Null hypothesis: mean of the post scores is equal or lower than the mean of the pre score.

Alternative hypothesis: mean of the post scores is higher the mean of the pre score.
POSTSCORE PRESCORE
129 148
147 154
147 135
140 164
157 132
144 150
147 154
156 143
151 139
144 132
144 136
149 122
128 151
154 134
145 134
131 135
158 135
153 150
140 147
146 135
133 125
169 131
152 115
131 172
144 149

Solutions

Expert Solution

Using Minitab software, (Stat -> Basic Statistics -> Paired t ), we get the following output -

Here,

The value of test statistic t = 1.22

and P-value = 0.118

Since P-value > 0.05, so we fail to reject H0 at 5% level of significance and we can conclude that mean of the post scores is not significantly higher the mean of the pre score

orchestra answered 2 years ago
Next > < Previous

Related Solutions

Perform the appropriate Hypothesis Test for the following (Be sure to have a null hypothesis (H0)...
Perform the appropriate Hypothesis Test for the following (Be sure to have a null hypothesis (H0) and alternate hypothesis; (H1). Explain how to find test statistic and P-value on the calculator; also Interpret the results (i.e. Reject or Fail to Reject H0), (Is or Is not significant evidence to support the claim H1). You want to see if all three college algebra classes have the same mean. Use the following data to test your claim at a .01 significance level....
In each of the following exercises, formulate an appropriate null hypothesis and perform a test of...
In each of the following exercises, formulate an appropriate null hypothesis and perform a test of that null hypothesis at the 5% and 1% significance levels. Use a one-sided or two-sided test as appropriate. 10. An instructor administers a 2-minute sit-up test to a class of 10 students, obtaining the following scores. X : 55,45,48,62,58,60,42,44,53,55 The instructor expects students to have an average score of no more than 45 on the sit-up test. Part (a) Assume that 10 is the...
a. Develop a null and alternative hypothesis for a test of whether or not the mean...
a. Develop a null and alternative hypothesis for a test of whether or not the mean of the data representing wives’ satisfaction scores and husbands’ satisfaction scores are statistically different. Find descriptive statistics on the three relevant variables in the table. Highlight the means, standard deviations, and observations. TABLE C9-2: Wife and Husband Feedback Scores on 1-7 Scale + Same Day or Not Appraisal Survey Wife's Score Husband's Score Same Day 1 4 5 Y 2 3 2 Y 3...
Use the ”test.vs.grade” data and test the null hypothesis that the mean test score for the...
Use the ”test.vs.grade” data and test the null hypothesis that the mean test score for the population is 70 against the alternative that it is greater than 70. Find a p-value and state your conclusion if α = 0.05. Repeat for the null hypothesis µ = 75. https://www.math.uh.edu/~charles/data/test.vs.grade.csv
Consider the following hypothesis test. The null hypothesis is "The mean body temperature for humans is...
Consider the following hypothesis test. The null hypothesis is "The mean body temperature for humans is 98.6 degrees Farenheit." and the alternative hypothesis is "The mean body temperature for humans differs from 98.6 degrees Farenheit." Answer the following questions. a. "The mean body temperature for humans in fact is 98.6 degrees Farenheit but the result of the sampling lead to the conclusion that the mean body temprature for humans differ from 98.6 degrees Farenheit" is a A. correct decision B....
A. Find the power of the test, when the Null Hypothesis assumes a population mean of...
A. Find the power of the test, when the Null Hypothesis assumes a population mean of Mu = 450, with a population standard deviation of 156, the sample size is 5 and the true mean is 638.47 with confidence intervals of 95 B. Find the power of the test, when the Null Hypothesis assumes a population mean of Mu = 644, with a population standard deviation of 174, the sample size is 3 and the true mean is 744.04 with...
A. Find the power of the test, when the Null Hypothesis assumes a population mean of...
A. Find the power of the test, when the Null Hypothesis assumes a population mean of Mu = 450, with a population standard deviation of 156, the sample size is 5 and the true mean is 638.47 with confidence intervals of 95 B. Find the power of the test, when the Null Hypothesis assumes a population mean of Mu = 644, with a population standard deviation of 174, the sample size is 3 and the true mean is 744.04 with...
Test the null hypothesis that the mean difference in the number of cases lost on appeal...
Test the null hypothesis that the mean difference in the number of cases lost on appeal for the two groups of judges is zero against the alternative hypothesis that the untrained judges lose more cases on appeal. Use an alpha level of .01. Judge Untrained Trained 1 3 0 2 1 3 3 2 4 4 7 4 5 5 2 6 4 5 7 6 1 8 2 1 9 7 0 10 5 6 11 3 4 12...
4. Suppose that we want to test the null hypothesis that the mean of a normal...
4. Suppose that we want to test the null hypothesis that the mean of a normal population with    σ2 =1. Ho: μ = 10 vs Ha: μ > 10.   Determine the minimum sample size needed to test with β(11) = 0.06.
Consider a general one-sided hypothesis test on a population mean µ with null hypothesis H0 :...
Consider a general one-sided hypothesis test on a population mean µ with null hypothesis H0 : µ = 0, alternative hypothesis Ha : µ > 0, and Type I Error α = 0.02. Assume that using a sample of size n = 100 units, we observe some positive sample mean x > 0 with standard deviation s = 5. (a) Calculate the Type II Error and the power of the test assuming the following observed sample means: (i) x =...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT