In: Chemistry
1. Without doing any calculations, choose the 0.12 M aqueous solutions with a pH of 2.
(Select all that apply.)
Mg(CH3COO)2
HNO2
NH4Cl
NaF
Ba(OH)2
NaHCO3
none of the above
2.
Without doing any calculations, choose the 0.12 M aqueous solutions with a pH between 2 and 6.
(Select all that apply.)
Mg(CH3COO)2
HNO2
NH4Cl
NaF
Ba(OH)2
NaHCO3
none of the above
Ans. #1. For getting a pH of 2.0 at 0.12M concertation, the acid must be a strong acid (like HCl, HNO3, etc.) with very high dissociation constant.
# Option A. Incorrect. Mg(CH3COO)2 is a salt of weak acid (acetic acid) and strong base. When dissolved in water, it dissociates into Mg2+ and 2 CH3COO-. The acetate ion CH3COO- acts conjugate base and accepts a proton from water as follow-
CH3COO-(aq) + H2O(l) -------> CH3COOH(aq) + OH-
Since the reaction forms OH- ions, the pH of solution rises above 7.0 and becomes basic.
# Option B. Incorrect. HNO2 is a weak acid with pKa of 3.14. So, the resultant solution shall have a pH above 3.4.
# Option C. Incorrect. NH4Cl. NH4Cl is a salt of weak base (NH3) and strong acid. The NH4+ ions act as conjugate acid in water as follow-
NH4+ + H2O -----> NH3 + H3O+
The solution is relatively acidic. However, since NH4+ is a weak conjugate acid (pKa of 9.9), the pH shall be around 5.0
# Option D. Incorrect. NaF is a salt of weak acid (HF) and strong base.
The fluoride ion, acting as conjugate base, reacts with water to produce OH- ion as follow-
F- + H2O -------> HF + OH-
So, the pH of solution is basic, above 7.0.
# Option E. Incorrect. Ba(OH)2 is a strong base. The resultant solution shall have a pH much above 7.0.
# Option F. NaHCO3. NaHCO3 is a salt of weak acid and strong base. It dissociates to produce HCO3-. HCO3- has a pKa of 10.33, i.e. it is a weaker acid than water. Therefore, HCO3- acts as a weak base in water. So, the resultant solution has a pH above 7.0.
# Correct option. None of the above.
#2. Correct option B. HNO2is a weak acid with pKa of 3.14. So, the resultant solution shall have a pH above 3.4.