In: Chemistry
Without doing any calculations, arrange the elements in FeCO3 in order of decreasing mass percent composition. (Highest to Lowest)
FeCO3 molecular weight = 115.85 g
Fe weight = 55.84 g
'C' weight = 12 g
'O' atom weight = 16 g
O3 weight = 48 g
mass percent of 'Fe' = ( Fe weight / FeCO3 weight ) x 100
= ( 55.84 / 115.85 ) x 100
= 48.2 %
mass percent of 'C' = ( C weight / FeCO3 weight ) x 100
= ( 12 / 115.85 ) x 100
= 10.36 %
mass percent of ' O' = ( 3 O atoms weight / FeCO3 weight ) x 100
= ( 48 / 115.85 ) x 100
= 41.43 %
mass percent decreasing order of atoms : Fe > O > C