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Without doing any calculations, arrange the elements in FeCO3 in order of decreasing mass percent composition....

Without doing any calculations, arrange the elements in FeCO3 in order of decreasing mass percent composition. (Highest to Lowest)

Solutions

Expert Solution

FeCO3 molecular weight = 115.85 g

Fe weight = 55.84 g

'C' weight = 12 g

'O' atom weight = 16 g

O3 weight = 48 g

mass percent of 'Fe' = ( Fe weight / FeCO3 weight ) x 100

                                  = ( 55.84 / 115.85 ) x 100

                                   = 48.2 %

mass percent of 'C' = ( C weight / FeCO3 weight ) x 100

                                  = ( 12 / 115.85 ) x 100

                                   = 10.36 %

mass percent of ' O' = ( 3 O atoms weight / FeCO3 weight ) x 100

                                  = ( 48 / 115.85 ) x 100

                                   = 41.43 %

mass percent decreasing order of atoms : Fe > O > C

queen_honey_blossom answered 1 year ago
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