In: Math
You are considering the risk-return profile of two mutual funds for investment. The relatively risky fund promises an expected return of 7.2% with a standard deviation of 15.7%. The relatively less risky fund promises an expected return and standard deviation of 3.9% and 6%, respectively. Assume that the returns are approximately normally distributed.
a-1. Calculate the probability of earning a negative return for each fund. (Round final answer to 4 decimal places.)Probability: Riskier fund and Less risky fund
a-2. Which mutual fund will you pick if your objective is to minimize the probability of earning a negative return?
Less risky or fund Riskier fund
b-1. Calculate the probability of earning a return above 8.3% for each fund. (Round final answer to 4 decimal places.) Probability Riskier fund and Less risky fund
b-2. Which mutual fund will you pick if your objective is to maximize the probability of earning a return above 8.3%?
Riskier fund or Less risky fund
Answer :
(a-1). For riskier is fund:
We first get the z score for the critical value
As z = (x - u) / s,
critical value = x = 0
mean =u =7.2
standard deviation = s = 15.7
Thus,
z = (x - u) / s
=((0-7.2)/15.7)
= -0.458598
Thus, using a table/technology, the left tailed area of this
is
P(z < -0.458598 ) = 0.21805555 [ANSWER]
** For less risky fund: We first get the z score for the critical value.
As z = (x - u) / s, then as
critical value =x = 0
mean =u = 3.9
standard deviation = s = 6
Thus,
z = (x - u) / s
= ((0-3.9)/6)
= -0.65.
Thus, using a table/technology, the left tailed area of this
is
P(z < -0.65. ) =-0.153846153[ANSWER].
( a-2). From part A, I will choose LESS RISKY FUND.
(b-1). For riskier fund:
We first get the z score for the critical value. As z = (x - u) / s,
were as
critical value =x = 7.2
mean = u = 7.2
standard deviation = s =15.7
Thus,
z = (x - u) / s = 0
by using a table/technology, the right tailed area of this is
P(z > 0 ) = 0.5 [ANSWER]
For less risky fund: We first get the z score for the critical value.
As z = (x - u) / s,
were as
critical value = x = 7.2
mean = u =3.9
standard deviation = s = 6
Thus,
z = (x - u) / s
=((7.2-3.9)/6)
= 6.55
by using a table/technology, the right tailed area of this is
P(z > 6.55 ) = -0.3076923076 [ANSWER] .
(b-2). From b-1, we choose RISKIER FUND. [ANSWER].