Calcuate the pH when 80 mL of 1.25 M HCL is added to 779 mL of...

Calcuate the pH when 80 mL of 1.25 M HCL is added to 779 mL of 1.60 M of sodium acetate.

Please show all calculations. Thanks! :)

Expert Solution

pH=-log[H+]

H+ ions produced only by HCl,so [H+]= no of moles of H+/total volume of solution

=n/V

=Molarity * volume of HCl added to the solution/V

=1.25 mol/L * (80 * 10^-3 L)/(80+779) * 10^-3 L

=100*10^-3 mol/859 * 10^-3 L

=0.1164 mol/L

pH=-log (0.1164)=0.934 answer

queen_honey_blossom answered 7 months ago

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