In: Chemistry
Calcuate the pH when 80 mL of 1.25 M HCL is added to 779 mL of 1.60 M of sodium acetate.
Please show all calculations. Thanks! :)
pH=-log[H+]
H+ ions produced only by HCl,so [H+]= no of moles of H+/total volume of solution
=n/V
=Molarity * volume of HCl added to the solution/V
=1.25 mol/L * (80 * 10^-3 L)/(80+779) * 10^-3 L
=100*10^-3 mol/859 * 10^-3 L
=0.1164 mol/L
pH=-log (0.1164)=0.934 answer