In: Chemistry
Determination of the Calcium Content of Beer and Water Using Atomic Absorption Spectroscopy
1. Assuming the wort is saturated with Ca3(PO4)2(s), what would happen to the concentration of Ca2+ions in the wort if: (i) More HPO42-ions were added? PO43- Concentration will increase (ii) Ca3(PO4)2 (s) was added? (iii) The pH of the solution was decreased by addition of a suitable acid?
2. Why is LaCl3 utilized? What changes would be needed in set up of the AAS if LaCl3 was not used
3. If your two highest concentrations for the calibration both have an absorbance of about 2, what is the problem and how you would correct it?
1)3)
If pH of the solution is decreased, then the protonated form will arise...So, the conversion of
will be facilitate...
Thus, instead of Ca3(PO4)2 , we will get soluble CaHPO4 . So , then as it is soluble, it will dissotiate into -
So, concentration of Ca2+ will increase.
3)
The absorbance is too high ( 2 ), that means, the concentration of target is too high.
Now, in such high concentration , the deviations of Bear's Law is observed due to assotiation etc. Then , we cannot accurately calculate oncentration just by using the callibration formula . So, at such high absorbance , we should not take the results for calculation . What we can do , is - We can quantitatively dilute the samples . Let say , exact 5 times dilution . Then if we record the absorbance , it will be good . Using that absorbance value, we can get the concentration of the diluted species . Now , as we had diluted quantitatively , so , by multiplying with the dilution factor ( here 5 ) , we can get the initial concentration of the sample .