Question

Suppose there are 5 links between sending host A and receiving host B, where each link has the same transmission rate R.

What is the end-to-end delay of sending 10 packets of length L from A to B? (Ignore propagation delay and nodal processing delay). Assume there are no other packets on the network.

Answer 1

Solution:

Given,

=>Number of links = 5

=>Transmission rate = R

=>Number of packets = 10

=>Size of each packet = L

Explanation:

=>Host A...link1...(s1)...link2...(s2)....link3....(s3)....link4....(s4)...link5..Host B

=>Here packet switching concept will be used by default.

=>First packet will require all the transmission delays of in between devices and host A and all other packets will required only one transmission delay by host A.

Calculating transmission delay:

=>Tranmission delay = packet length/transmission rate

=>Tranmission delay = L/R

Calculating total delay for first packet:

=>Total delay for first packet = 5*transmission delay

=>Total delay for first packet = 5*(L/R)

Calcualting delay for other 9 packets:

=>Total delay for 9 packet packets = 9*transmission delay

=>Total delay for 9 packet packets = 9*(L/R)

Calculating total delay for 10 packets:

=>Total delay for 10 packets = 5*(L/R) + 9*(L/R)

=>Total delay for 10 packets = 14*(L/R)

I have explained each and every part with the help of statements attached to it.